This is how to solve the problem: "What is the transformations of f(x)=(x-2)^2-4"
Looking at the quadratic equation given,
f(x) = (x-2)^2 - 4
It's like seeing product of sum and difference of two squares.
(x-2)^2 - 4
[ (x-2) - 2 ] [ (x-2) + 2 ]
[ x - 2 - 2 ] [ x - 2 + 2 ]
[ x - 4 ] [ x ]
[ x^2 - 4x ]
So the final transformation of f(x) = (x-2)^2 -4 is f(x) = (x^2 - 4x).
In this way, we are able to show how a complicated equation to simple yet equal equation in quadratic form.
the question does not present the options, but this does not interfere with the resolution
we have
sin x/ (1-cos x)
we know that
sin²x+cos²x=1-----------> sin²x=1-cos²x
and
difference of squares
(a+b)*(a-b)=a²-b²
so
The idea is to make the difference of squares (1-cos²x)in denominator.so
multiply the expression by (1+cos x)/(1+cos x)
[sin x/ (1-cos x)]*[(1+cos x)/(1+cos x)]=[sin x*(1+cos x)]/[ (1-cos x)/(1+cos x)]
=[sin x*(1+cos x)]/[ (1-cos²x)]
=[sin x*(1+cos x)]/[ sin²x]
=(1+cos x)/sin x
=(1/sin x)+(cos x/sin x)
=csc x+cot x
therefore
the answer is
the first step is multiply the expression by (1+cos x)/(1+cos x)
Answer:
p=$15000
R=15%
t=5years
compound amount CI=?
Step-by-step explanation:
we have
- CI=p(1+R/100)^t=$15000(1+15/100)^5=$15000×1/15^5=$30170.35
