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beks73 [17]
3 years ago
11

Use benchmarks to estimate the sum, difference, or product.\

Mathematics
1 answer:
sammy [17]3 years ago
6 0
1 7/8 + 1/9 = 143/72 and simplify it and u get 1 71/72

8 8/9 - 5 1/11 = 376/99 and simplify it and u get 3 79/99

7 1/13 * 4 15/17 = 7636/221 and simplify it and u get 34 122/221

hope this helps
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Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AC is the only key for R, identify each of these FD's from the f
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Given that R(ABCDE) is in Boyce-Codd normal form.

And AB is the only key for R.

Definition

A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is

a

Given that AB is the only key for R.

ABC E (Yes).

check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.

2) ACE B

(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.

ACE B

is

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3) ACDE → B           (NO)

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As there is no AB in BC ~. B(→ not in BCNF

BC is not a super key.

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Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.

1. ABC E

2. ACE B

3. ACDE B

4. BC C

5. ABD E

Learn more about Boyce-Codd Normal Form at

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