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Nadusha1986 [10]
2 years ago
12

Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AC is the only key for R, identify each of these FD's from the f

ollowing list. Answer Yes or No and MUST explain your answer to receive points
Mathematics
1 answer:
Goshia [24]2 years ago
6 0

Given that R(ABCDE) is in Boyce-Codd normal form.

And AB is the only key for R.

Definition

A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is

a

Given that AB is the only key for R.

ABC E (Yes).

check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.

2) ACE B

(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.

ACE B

is

Boyce-Codd Normal Form not in BENE (NO)

3) ACDE → B           (NO)

check if is a super key. ACDE

As ACDE there is not any AB Tn ACDE. a super key.

ACDEB is not in BCNF.

4) BS → C → (NO)

As there is no AB in BC ~. B(→ not in BCNF

BC is not a super key.

5) ABDE (Yes).

Since AB is a key.

ABO TS a super key.

.. ABDE → E is in BCNF

Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.

1. ABC E

2. ACE B

3. ACDE B

4. BC C

5. ABD E

Learn more about Boyce-Codd Normal Form at

brainly.com/question/14299832

#SPJ4

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How do you solve the mean absolute deviation of 4,2,9,3,1,8
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Step 1: Calculate the mean of the given observation.

\text{Mean}=\frac{\text {Sum of the observation}}{\text {Number of observation}}

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The image of this step is attached below.

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