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Yuliya22 [10]
3 years ago
9

A company ships coffee mugs using boxes in the shape of cubes. The function g(x) = gives the side length, in inches, for a cube

with a volume of x cubic inches. Suppose the company decides to double the volume of the box. Which graph represents the new function?

Mathematics
2 answers:
Gekata [30.6K]3 years ago
3 0

Answer:

The graph is attached below.

Step-by-step explanation:

The volume of the box containing the coffee mugs is,

V=x^{3}

Then the function representing the side length, in inches, for the box is:

g(x)=x

Now, it is provided that the company decides to double the volume of the box.

That is, the new volume will be:

V_{n}=2x^{3}

Then the side length, in inches, for the box will be:

g_{n}(x)=\sqrt[3]{2x^{3}} =\sqrt[3]{2}x

Then the graph representing the function, formed using the following points is:

x\ \ \ \ \ \ \ \ \ g_{n}(x)\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\0\ \ \ \ \ \ \ \ \ \ \ 0\\1\ \ \ \ \ \ \ \ \ \ \ 2^{1/3}

Pavlova-9 [17]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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Sergio039 [100]

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From the question, we are to match the base to the corresponding height

In a triangle, the height of the triangle is perpendicular to the base.

Applying this in the given diagram,

The first base matches the second height

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2 years ago
The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.
puteri [66]

Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  3. Exponents
  4. Multiplication
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Area of a Rectangle: A = lw

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Derivatives

Derivative Notation

Implicit Differentiation

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Derivative Rule [Product Rule]:                                                                              \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

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Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

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kirill [66]
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The above is the answer :)
(btw sorry in advance if you've spotted a mistake)
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