Answer: y= - 4x+18
Step-by-step explanation:
Equation: y=mx+b
***remember: b is the y-intercept and m is the slope.
m=
3= x1
2= x2
6= y1
10=y2
m=
= 
= -4
m=-4
Now we have y=-4x+b , so let's find b.
You can use either (x,y) such as (3,6) or (2,10) point you want..the answer will be the same:
(3,6). y=mx+b or 6=-4 × 3+b, or solving for b: b=6-(-4)(3). b=18.
(2,10). y=mx+b or 10=-4 × 2+b, or solving for b: b=10-(-4)(2). b=18.
Equation of the line: y=-4x+18
Answer:
B
Step-by-step explanation:
It is complementary because adding DEQ and REQ together adds up to 90 degrees
A RATIONAL NUMBER ! i hope i helped
Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.
For two lines y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate k1 and k2.
To calculate the slope k of any line, you have to change the equation to y=kx+b
For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))
For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)
Now you can get the answer: The two lines neither parallel nor perpendicular.
542 beacuse 142+400
4+1=5 4+0=a 2+0=2
