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kumpel [21]
4 years ago
9

Can someone explain this to me? I don't understand how they got from what I labeled 1 to what is labeled 2. Where did the 1/3 co

me from?

Mathematics
2 answers:
bixtya [17]4 years ago
4 0

Answer:

see attached

Step-by-step explanation:

see attached

worty [1.4K]4 years ago
3 0

Step-by-step explanation:

Using exponent rules:

3^(n+1) = 3^(n) 3^(1)

So:

3^n / 3^(n+1)

= 3^n / (3^n × 3)

= 1 / 3

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A car run 3/4 mile per minute another car can run 4/5 mile per minute.what is the difference in speed in miles per hour?
dybincka [34]

Answer:

3 miles per hour

Step-by-step explanation:

We need to subtract the two numbers to find the difference in speeds

4/5 - 3/4

We need to get a common denominator of 20

4/5 *4/4 - 3/4 *5/5

16/20 - 15/20

1/20  

The car going 4/5 miles per minute is going 1/20 miles per minute faster than the car going 3/4 miles per minute.

The question asks for miles per hour, not miles per minute.  We know  that there are 60 minutes per hour.

1/20 miles per minute * 60 minutes / hour

60/20 miles/hour

3 miles/ hour

The car going 4/5 miles per minute is going 3 miles per hour faster than the car going 3/4 miles per minute.

3 0
4 years ago
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Travka [436]

Answer: thank you

Step-by-step explanation: have a good day :)

7 0
3 years ago
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A floor lamp costs $21 less than a $99 painting. How much does the floor lamp cost?
lesya [120]
99-21=78

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6 0
3 years ago
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100.5 divided by 1.5
wariber [46]
The answer to 100.5 divided by 1.5 is 67
5 0
3 years ago
Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx
Alisiya [41]
\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}

\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}

3 0
3 years ago
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