Answer:
Ф = 0 and Ф = π
Step-by-step explanation:
* Lets explain how to solve the problem
∵ sin Ф + 1 = cos²Ф, where 0 ≤ Ф < 2π
- To solve we must to replace cos²Ф by 1 - sin²Ф
∵ sin²Ф + cos²Ф = 1
- By subtracting sin²Ф from both sides
∴ cos²Ф = 1 - sin²Ф
- Lets replace cos²Ф in the equation above
∴ sin Ф + 1 = 1 - sin²Ф
- Subtract 1 from both sides
∴ sin Ф = - sin²Ф
- Add sin²Ф for both sides
∴ sin²Ф + sin Ф = 0
- Take sin Ф as a common factor from both sides
∴ sin Ф(sin Ф + 1) = 0
- Equate each factor by 0
∵ sin Ф = 0
∴ Ф = 0 OR Ф = 2π
∵ sin Ф + 1 = 0
- Subtract 1 from both sides
∴ sin Ф = -1
∴ Ф = π
∵ 0 ≤ Ф < 2π
∵ Ф < 2π
∴ We will refused the answer Ф = 2π
∴ Ф = 0 and Ф = π
Answer:
Discount= original price-sale price
Step-by-step explanation:
Hence D = AED149-AED110
D= AED 39
<u>Answer:</u>
○ 1 hour 41 minutes or more
<u>Step-by-step explanation:</u>
We can make two equations that represent the total amount each plumber charges.
If 
represents the number of hours they work, then:
•Total charged by Plumber A = 
• Total charged by Plumber B = 
Now, if Plumber A is more expensive than Plumber B, then:
Total charged by Plumber A > Total charged by Plumber B
∴ >
Now all we have to do is solve for :
>
⇒ 
⇒ 
⇒ 
⇒ 
is equivalent to 
= 100 minutes, which is the same as 1h 40min.
This means if Plumber A works more than 1h 40min, they become more expensive than Plumber B.
More than 1h 40min is equivalent to '1 hour 41 minutes or more', therefore the first option is correct.
10/1 as a mixed number is just 10
A:4*7=28. so there are 7 multiples upto 30. P(A)=7/30
B:26,27,28,29 i.e. 4 numbers satisfy the 2nd criteria. P(B)=4/30
P(A∩B)=1/30 (since 28 belongs to both A&B)
P(A∪B)= P(A)+P(B)-P(A∩B)= (7+4-1)/30= 1/3
