The rate would be
22000 gallons per 16 hours or
rate = 22000/16 = 1375 gallons/hr
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer:
-12.8x - 20y + 8.4
Step-by-step explanation:
To do this you just multiply everything by negative 4
so we have 3.2x*-4 + 5y*-4 - 2.1*-4
This gives us
-12.8x - 20y + 8.4
The last term is positive because we multplied a negative by another negative
Answer:
b=
Step-by-step explanation:
Considering the given figure the sides 'b' , '2' and '5' are making the sides of a right angled triangle in the top right corner of the square, where
Hypotenuse=5 , Perpendicular=b and Base=2
Using Pythagoras Theorem:
Implementing the values in the formula:
So, the value of 'b' is which is same for the the given 'b' in the figure.
please see the attached picture for full solution
hope it helps
good luck on your assignment