Are you sure that’s the problem?
Answer:
36 minutes past 1, or 1:36
Step-by-step explanation:
A watch normally has an hour hand that does one revolution in 12 hours.
It takes 1 hour to go from the 1 o'clock position to the 2 o'clock position.
Since 1 hour equals 60 minutes, it takes 60 minutes to go from the 1 o'clock position to the 2 o'clock position.
The hour hand is 3/5 of the way from 1 to 2, so the number of minutes past 1 o'clock is 3/5 of 60 minutes.
3/5 of 60 minutes =
= 3/5 * 60 minutes
= 3/5 * 60/1 minutes
= 180/5 minutes
= 36 minutes
The time is 36 minutes past 1, or 1:36
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Answer:
If its a cube function. Then I think this is the answer. Can you mark brainliest? And can you tell me if it's right or wrong?
Step-by-step explanation:
Consider the cubic function f(x) = ax^3 + bx^2 + cx + d. Determine the values of the constants a, b, c and d so that f(x) has a point of inflection at the origin and a local maximum at the point (2,...
Consider the cubic function f(x) = ax^3 + bx^2 + cx + d. Determine the values of the constants a, b, c and d
so that f(x) has a point of inflection at the origin and a local maximum at the point (2, 4). ==>c=3
