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just olya [345]
3 years ago
6

The chubby bunny weighs 5 pounds, and it gains 3 pounds per year. The fat cat weighs 19 pounds, and it gains 1 pound per year. W

hen will the two animals weigh the same amount?
Mathematics
1 answer:
masya89 [10]3 years ago
7 0

Answer: 7 years

Step-by-step explanation:

The Chubby bunny currently weighs 5 pounds but is increasing by 3 pounds per year. Assuming we wanted to find the weight in a given year, we can assume that given year is x. The expression would be:

= 5 + 3x

The fat cat weighs 19 pounds and gains by 1 pound a year.

Expression is:

= 19 + 1x

Equate the two equations together and find x:

5 + 3x = 19 + 1x

3x - 1x = 19 - 5

2x = 14

x = 14/2

x = 7 years

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5<br>the square root of 55<br>7<br>the square root of 32<br>​
puteri [66]

Answer:

the square root of 55, or 7.42

Step-by-step explanation:

Use the Pythagorean Theorem, or  a²+b²=c², where a and b are the sides or "legs" of the triangle and c is the hypotenuse.

a is 3, b is x, and c is 9

If you plug that into the equation, you get 3²+x²=8²

We can make this 9+x=64 by squaring the 3 and 8.

Then we can subtract 9 from each side to get x=55.

Finally, take the square root of 55 to get √55 or 7.42.

I hope this helped!

8 0
4 years ago
What is the next term of the arithmetic sequence? 7,11,15,19,7,11,15,19
natima [27]

Answer:

7

Step-by-step explanation:

4 times at an addition of 4, then a subtraction of 12

8 0
3 years ago
What is the ratio of 50 and 30 girl
choli [55]
Do you mean simplified ratio of 50:30, because if you did then the simplified ratio of 50:30 would be 5:3. Divide both numbers by 10. 
5 0
3 years ago
If x&gt;2, then x^2-x-6/x^2-4=
Viefleur [7K]
Consider the expression \frac{x^{2} -x-6}{ x^{2} -4}

To factorize the expression in the denominator we use difference of squares: x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)

To factorize x^{2} -x-6 we use the following method:

x^{2} -x-6=(x-a)(x-b)

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)

&#10; \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2}


\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}

for x>2

\frac{1}{x+2}\ \textless \  \frac{1}{2+2}= \frac{1}{4}

thus

for x>2, 

1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4}


Answer: 

for x>2

\frac{x^{2} -x-6}{ x^{2} -4} =  \frac{x+3}{x+2} \ \textless \  \frac{5}{4}, (but the expression is never 0)
8 0
4 years ago
How many centimeters are in six hundred millimeters?
olga55 [171]
60 cm are in 600 mm.
6 0
3 years ago
Read 2 more answers
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