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marshall27 [118]
3 years ago
13

I need some help with this problem, #18. Can someone help me please??

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0
Givens
<FOP = 2x + 2
<POQ = 10x - 8
<OF is bisects POQ

Comment
If you multiply POF (which is 2x + 2) by 2 it will be the same size as <POQ because POF is one of the bisected angles of < POQ.

Create an equation and solve
2(2x + 2) = 10x - 8     Remove the brackets.
4x  + 4 = 10x - 8        Add 8 to both sides.
4x + 4 + 8 = 10x        Combine like terms.
4x + 12 = 10x            Subtract 4x from both sides.
12 = 10x - 4x 
12 = 6x                      Divide by 6
x = 12/ 6
x = 2 <<<< answer A

Find <POF
< POF = 2x + 2
< POF = 2(2) + 2
<POF = 4 + 2
<POF = 6   <<<< answer B

Find <QOF
<QOF = <POF
<QOF = 6 <<<<< Answer C
        
Find <POQ
<POQ = 10x - 8
<POQ = 10(2) - 8
<POQ = 20 - 8
<POQ = 12 <<<<< Answer D





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4b - 5 + (-a-3) i = 7 * 8i
Rudik [331]

Answer:

Simplifying

4b + -5 + (-1a + -3) * i = 7 + -8i

Reorder the terms:

4b + -5 + (-3 + -1a) * i = 7 + -8i

Reorder the terms for easier multiplication:

4b + -5 + i(-3 + -1a) = 7 + -8i

4b + -5 + (-3 * i + -1a * i) = 7 + -8i

Reorder the terms:

4b + -5 + (-1ai + -3i) = 7 + -8i

4b + -5 + (-1ai + -3i) = 7 + -8i

Reorder the terms:

-5 + -1ai + 4b + -3i = 7 + -8i

Solving

-5 + -1ai + 4b + -3i = 7 + -8i

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + -1ai + 4b + 5 + -3i = 7 + 5 + -8i

Reorder the terms:

-5 + 5 + -1ai + 4b + -3i = 7 + 5 + -8i

Combine like terms: -5 + 5 = 0

0 + -1ai + 4b + -3i = 7 + 5 + -8i

-1ai + 4b + -3i = 7 + 5 + -8i

Combine like terms: 7 + 5 = 12

-1ai + 4b + -3i = 12 + -8i

Add '-4b' to each side of the equation.

-1ai + 4b + -4b + -3i = 12 + -4b + -8i

Combine like terms: 4b + -4b = 0

-1ai + 0 + -3i = 12 + -4b + -8i

-1ai + -3i = 12 + -4b + -8i

Add '3i' to each side of the equation.

-1ai + -3i + 3i = 12 + -4b + -8i + 3i

Combine like terms: -3i + 3i = 0

-1ai + 0 = 12 + -4b + -8i + 3i

-1ai = 12 + -4b + -8i + 3i

Combine like terms: -8i + 3i = -5i

-1ai = 12 + -4b + -5i

Divide each side by '-1i'.

a = -12i-1 + 4bi-1 + 5

Simplifying

a = -12i-1 + 4bi-1 + 5

Reorder the terms:

a = 5 + 4bi-1 + -12i-1

4 0
2 years ago
Read 2 more answers
Joe owns a stock which has probability .5 of going up. This morning, he bought a ticket in a lottery game which gives him a prob
Anit [1.1K]

Answer:

The probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

Step-by-step explanation:

Let the events be denoted as:

<em>X</em> = the stock goes up

<em>Y</em> = Joe wins the lottery

Given:

P (X) = 0.50

P (Y) = 0.0001

The events of the stock going up is not dependent on the the event of Joe winning the lottery.

So the events <em>X</em> and <em>Y</em> are independent of each other.

Independent events are those events that can occur together at the same time.

The joint probability of two independent events <em>A</em> and <em>B </em>is,

P(A\cap B)=P(A)\times P(B)

Compute the value of P (<em>X ∩ Y</em>) as follows:

P(X\cap Y)=P(X)\times P(Y)=0.50\times 0.0001=0.00005

Thus, the probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

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3 years ago
Read 2 more answers
Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an
Alexxx [7]

Answer:

<u>a. s.e. = 0.338</u>

<u>b. The  probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%</u>

<u>c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%</u>

d. <u>The sample mean of 62.75 would represent the 15th percentile</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

<u>s.e. = 0.338</u>

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

<u>The  probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%</u>

4.  What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

<u>p (z = -1.48) = 0.0694</u>

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

<u>The sample mean of 62.75 would represent the 15th percentile</u>

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2 years ago
One Digit Quotient<br>Plz Help Ugh
Nikitich [7]
8.8 rounding the remainder
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3 years ago
Cual es el resultado de (7.006×10⁴¹)×(5.09×10²²)<br><br>​
Murljashka [212]

Answer:

El resultado de (7.006×10⁴¹)×(5.09×10²²)=3.566054*10⁶⁴

Step-by-step explanation:

La notación científica es una manera rápida de representar un número utilizando potencias de base diez.

Los números se escriben como:

a*10ⁿ

donde:  

  • a es un número real mayor o igual que 1 y menor que 10.
  • n es un número entero, que recibe el nombre de exponente u orden de magnitud. Representa el número de veces que se desplaza la coma. Siempre es un número entero, positivo si se desplaza a la izquierda, negativo si se desplaza a la derecha.

Para realizar la multiplicación con notación científica, debes multiplicar las magnitudes afectadas por las potencias de 10 y, por separado, multiplicar las potencias de 10, recordando la propiedad:

  • Si dos bases son iguales (el mismo número o variable), y son los factores de una multiplicación, ambas bases quedan en una sola y sus exponentes son sumados: xᵃ*xᵇ= xᵃ⁺ᵇ

En este caso:

(7.006×10⁴¹)×(5.09×10²²)=(7.006*5.09)*(10⁴¹*10²²)=35.66054*10⁴¹⁺²²= 35.66054*10⁶³

Siguiendo el formato a*10ⁿ, debes ajustar el valor de la base a de manera que sea un número real mayor que 1 y menor que 10. Entonces, se mueve la coma decimal hacia la izquierda tantos espacios hasta llegar a la derecha del primer dígito.  Y se escribe la base 10, al cual el exponente se suma la cantidad de espacios que se mueve la coma, que es un número positivo porque la coma se desplaza a la izquierda.

Entonces 35.66054*10⁶³= 3.566054*10⁶⁴

<u><em>El resultado de (7.006×10⁴¹)×(5.09×10²²)=3.566054*10⁶⁴</em></u>

4 0
3 years ago
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