Answer:
the ...ha answer is =99 in.^3
Factor out the GCF
12x^2(x + 1) = 0
Now you can do two parts
12x^2 = 0, x = 0
x + 1 = 0, x = -1
Solution: x = 0, x = -1
Answer:
–3x + 22
Step-by-step explanation:
x + 2(x – [3x – 8] + 3)
x + 2(x – 1[3x – 8] + 3)
x + 2(x – 1[3x] – 1[–8] + 3)
x + 2(x – 3x + 8 + 3)
x + 2(–2x + 11)
x + 2(–2x) + 2(+11)
x – 4x + 22
1x – 4x + 22
–3x + 22
Answer:
The largest integer is 29.
Step-by-step explanation:
Let the consecutive positive integers are x, x+1 and x+2.
The square of sum of squares of three consecutive positive integers is 2354 such that,

It is a quadratic equation whose solution is given by :
x = 27 and x = -29
First positive integer = 27
Second positive integer = 27+1 = 28
Third positive integer = 27+2 = 29
Hence, the largest integer is 29.