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bonufazy [111]
2 years ago
14

I need to know the equation?

Mathematics
2 answers:
Oliga [24]2 years ago
7 0
55+8.50x=123
x = Number of days Val rented
liberstina [14]2 years ago
6 0
$55.00+$8.50=x x=$123
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Please help I will reward Brainliest
Sauron [17]

Answer:

5.32

Step-by-step explanation:

a^2+b^2=c^2

a^2+4.7^2=7.1^2

a+22.09=50.41

50.41-22.09=28.32

a=5.32

6 0
3 years ago
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For which equations is 8 a solution? Select the four correct answer
maxonik [38]

Answer:

I <em>believe</em> the answers are= 2, 3, 6, 8

Step-by-step explanation:

For #2, you would subtract 2 from both sides. 10-2=8. x=8.

For #3, you would add 4 to both sides of the equation, making the final answer: x=8

For #6, you would divide both sides by 3. 24 divided by three is 8.

For #8, I multiplied the whole equation by 8, which is the denominator of x/8. 1 times 8=8. The final answer would be x=8.

Hope this helps!  

8 0
2 years ago
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876,302 to the nearest 10,000
Nataliya [291]

Answer:

Simple answer: 880,302

Step-by-step explanation:

Rule is if the number before the number your rounding is above 4 then it should round up

if its lower than 4 the number your rounding stays as is and the number before it goes down to 0

5 0
2 years ago
Rafael, Denise, and Philippe are doing a project together. They decide to base the project on a book that is 540 pages long. Raf
trasher [3.6K]
B.240, because 240+180+120=540
8 0
3 years ago
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A police department in a small city consists of 10 officers. If the department policy is to have 5 of the officers patrolling th
meriva

Answer:

2,520

Step-by-step explanation:

The number of possible arrangements of officers patrolling the streets is the combination of choosing 5 officers out of 10 (₁₀C₅). After choosing the patrolling officers, the number of arrangements for the officers working full time at the station is given by the combination of choosing 2 officers out of the 5 remaining (₅C₂). The remaining officers should be on reserve at the station (₃C₃). The total number of arrangements is:

N = _{10}C_5*_5C_2*_3C_3\\N=\frac{10!}{(10-5)!5!} *\frac{5!}{(5-2)!2!}*\frac{3!}{(3-3)!3!} \\N=2,520

There are 2,520 possible divisions.

5 0
3 years ago
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