Answer:
The end of the flagpole is 50.79 ft away from the base of the pole.
Step-by-step explanation:
The problem is represented by the diagram below.
The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).
The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).
Using Pythagoras theorem, we have that:
=> 
The end of the flagpole is 50.79 ft away from the base of the pole.
The correct answer is
the flagpole is <span>
33 feet high</span>.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is
33 feet high.
First you multiply 2and3/8 by 4 and which you will get 3 then you subtract 23 and 3 and get 20
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