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Sav [38]
3 years ago
8

5x+ 4y = -20 5x + 12y = -10 HELPPPPPP

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

We are to find x and y in this equation.

5x+4y= -20.

- 5x+12y= -10.

which is y=5/4 or 1.25.

then substitute y=1.25 into eqtn I.

5x+4(1.25)=-20.

5x+5= -20.

5x=-20-5.

5x= -25.

x= -5.

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Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving
harina [27]

Answer:

The volume of the solid is 714.887 units³

Step-by-step explanation:

* Lets talk about the shell method

- The shell method is to finding the volume by decomposing

 a solid of revolution into cylindrical shells

- Consider a region in the plane that is divided into thin vertical

 rectangle

- If each vertical rectangle is revolved about the y-axis, we

 obtain a cylindrical shell, with the top and bottom removed.

- The resulting volume of the cylindrical shell is the surface area

  of the cylinder times the thickness of the cylinder

- The formula for the volume will be:  V = \int\limits^a_b {2\pi xf(x)} \, dx,

  where 2πx · f(x) is the surface area of the cylinder shell and

  dx is its thickness

* Lets solve the problem

∵ y = x^{\frac{5}{2}}

∵ The plane region is revolving about the y-axis

∵ y = 32 and x = 0

- Lets find the volume by the shell method

- The definite integral are x = 0 and the value of x when y = 32

- Lets find the value of x when y = 0

∵ y = x^{\frac{5}{2}}

∵ y = 32

∴ 32=x^{\frac{5}{2}}

- We will use this rule to find x, if x^{\frac{a}{b}}=c, then=== x=c^{\frac{b}{a}} , where c

 is a constant

∴ x=(32)^{\frac{2}{5}}=4

∴ The definite integral are x = 0 , x = 4

- Now we will use the rule

∵ V = \int\limits^a_b {2\pi}xf(x) \, dx

∵ y = f(x) = x^(5/2) , a = 4 , b = 0

∴ V=2\pi \int\limits^4_0 {x}.x^{\frac{5}{2}}\, dx

- simplify x(x^5/2) by adding their power

∴ V = 2\pi \int\limits^4_0 {x^{\frac{7}{2}}} \, dx

- The rule of integration of x^{n} is ==== \frac{x^{n+1}}{(n+1)}

∴ V = 2\pi \int\limits^4_0 {x^{\frac{9}{2}}} \, dx=2\pi[\frac{x^{\frac{9}{2}}}{\frac{9}{2}}] from x = 0 to x = 4

∴ V=2\pi[\frac{2}{9}x^{\frac{9}{2}}] from x = 0 to x = 4

- Substitute x = 4 and x = 0

∴ V=2\pi[\frac{2}{9}(4)^{\frac{9}{2}}-\frac{2}{9}(0)^{\frac{9}{2}}}]=2\pi[\frac{1024}{9}-0]

∴ V=\frac{2048}{9}\pi=714.887

* The volume of the solid is 714.887 units³

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The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars ea
Gre4nikov [31]
A) zeroes

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Extract common factor:

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Factor (find two numbers that sum -10 and its product is 21)

P(n) = -250(n - 3)(n - 7)

Zeroes ==> n - 3 = 0  or n -7 = 0
Then n = 3 and n = 7 are the zeros.

They rerpesent that if the promoter sells tickets at 3  or 7 dollars the profit is zero.

B) Maximum profit

Completion of squares

n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4

P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000

Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000

Maximum profit =1000 at n = 5

C) Axis of symmetry

Vertex = (h,k) when the equation is in the form A(n-h)^2 + k

Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000

Vertex = (5, 1000) and the symmetry axis is n = 5.



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The grades on the last history exam had a mean of 75%. Assume the population of grades on history exams is known to be normally
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