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KonstantinChe [14]
3 years ago
10

For children who do not have galactosemia, what are their possible genotypes for this trait?

Biology
2 answers:
Sav [38]3 years ago
6 0

Answer:

its heterozygous and homozygous dominant

Explanation:

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

The correct answers are "heterozygous", and "homozygous dominant".

Explanation:

Galactosemia is a condition where people are not able to process the sugar galactose. People with this condition have one gene mutated, which does not allow the proper synthesis of the enzyme that breaks down galactose. Galactosemia is inherited as an autosomal recessive genetic condition, therefore, only children that are homozygous recessive develop the condition. Children that are heterozygous or homozygous dominant, will not develop galactosemia.

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The rate at which the concentration of a drug in the bloodstream decreases is proportional to the concentration at any time t. I
Westkost [7]

Answer:

C(t) = C_oe^{-kt}

Explanation:

From the given information:

At any given time (t), let c(t) represent the concentration of the drug present in bloodstream.

Deriving the equation:

\dfrac{dC}{dt} decrease proportionally to Concentration C

i.e

\dfrac{dc}{dt} \alpha - C

\dfrac{dc}{dt} = -k C

\dfrac{dc}{c} = -k dt

\int \dfrac{dc}{c} = -k \int dt

㏑(C) = -kt + λ

where,

λ is the integration constant.

Integrating at t = 0, concentration of blood = Co g/mL

C(0) = Co

㏑(C₀) = 0 + λ

λ = ㏑(C₀)

From ㏑(C) = -kt + λ

㏑(C) = -kt + ㏑C₀

㏑(C)  - ㏑C₀ =  -kt

\dfrac{C}{C_o} = e^{-kt}

C(t) = C_oe^{-kt}

∴

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C(t) = C_oe^{-kt}

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