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nexus9112 [7]
3 years ago
7

What is 4/9 - 1/12 least common moltiple

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

\frac{4}{9} -\frac{1}{12} = \frac{4.4}{9.4} - \frac{1.3}{12.3} = \frac{16}{36}- \frac{3}{36} = \frac{13}{36}

ok done. Thank to me :>

levacccp [35]3 years ago
3 0

Answer:

36

Step-by-step explanation:

The LCM of 4, 9, and 12 is the product of all prime numbers on the left, i.e. LCM(4, 9, 12) by division method = 2 × 2 × 3 × 3 = 36.

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Type the correct answer in each box. Use numerals instead of words.
MrRa [10]

Answer:

4 Blue chips

6 Yellow chips

10 Red chips

Imagine 20% as 2 of 10. We have 20 chips, and that's double of that. So if we have 2/10... we will have 4/20

Same with the yellow chips. Imagine 30% as 3 of 10, again double that... 6/20.

It doesn't directly say the percent of design a computer representation but we can infer that if we have 20% and 30%... that makes 50%, there is only 100 in a percent, so that means there is 50% left! We repeat the process where we envision 50% as 5 of 10, double that. Now we have 10 of 20, 50%!

4 0
3 years ago
What is the value of sin(60°+0) - sin(60°+0)?
neonofarm [45]

Answer:

0

Step-by-step explanation:

Let us take sin(60 degree + theta) =x

Substituting x in equation

=> x-x

=> 0

3 0
3 years ago
Read 2 more answers
(2x +1) -7 (-6x+9) what is the answer if using the Distributive Property?
Margarita [4]

Answer:

Step-by-step explanation:

Distributive property:  a(b +c) = a*b + a*c

(2x + 1) - 7(-6x + 9) = (2x + 1) + (-7)*(-6x) + (-7)*9

                              = 2x + 1 + 42x - 63  {Combine like terms}

                              = 2x + 42x + 1 - 63

                              = 44x - 62

5 0
3 years ago
Suppose that the trace of a 2×2 matrix a is tr(a)=15 and the determinant is det(a)=50. find the eigenvalues of
IrinaK [193]
Recall that the characteristic polynomial of a 2x2 matrix \mathbf A=\begin{bmatrix}a&b\\c&d\end{bmatrix} is

\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)

but \det(\mathbf A)=ad-bc and \mathrm{tr}(\mathbf A)=a+d, so the characteristic polynomial for \mathbf A is

\lambda^2-\mathrm{tr}(\mathbf A)\lambda+\det(\mathbf A)

We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is

\lambda^2-15\lambda+50

and the eigenvalues are those \lambda for which the characteristic polynomial evaluates to 0.

\lambda^2-15\lambda+50=(\lambda-5)(\lambda-10)=0\implies\lambda=5,\lambda=10
5 0
3 years ago
Solve with steps<br> 5^(x+3)=25^(x-2)
Taya2010 [7]

5^(x+3)=25^(x-2)

Apply the exponent rule ( 5 ^2 = 25, so remove the 5 and replace 25?with 2)


x + 3 = 2(x-2)

Simplify:

X + 3 = 2x -4

Add 4 to both sides:

X + 7 = 2x

Subtract x from both sides

X = 7


Answer: x = 7

6 0
2 years ago
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