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jasenka [17]
3 years ago
10

I need help with 7-12

Mathematics
1 answer:
Anton [14]3 years ago
8 0
7). C

8). 60
n = 5(10) + 10
n = 50 + 10
n = 60

9). 17
f(x) = -2x + 7 plug the -5 in for x
f(x) = -2(-5) + 7
= 10 + 7
= 17

10).
28.50j < 100 > 18.50s
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Kendrick and Rishaun spend a total of $112 at an amusement park. They spend $32 on parking, $12 on lunch, and the rest on 2 admi
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Each ticket is $34 each
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B) Determine the capacity of a rectangular box with a base area of 2m by 3 m and a height of 50
Nastasia [14]

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3m cube

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l = 2m

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Find the local max and min values of f(x)=x^2/x-1 using both first and second derivative tests
uranmaximum [27]
Hmm, the 2nd derivitve is good for finding concavity

let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient

so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x

so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points

f'(-1)>0
f'(1.5)<0
f'(3)>0

so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)


we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense




local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
6 0
3 years ago
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