Answer:
Step-by-step explanation:
The number of parrots in t years after 2010 can be modeled by the following function:
In which P(0) is the number of parrots in 2010 and r is the growth rate, as a decimal.
608 parrots in the forest in 2010.
This means that 
Then
When the scientists went back 5 years later, they found 4617 parrots.
This means that 
We use this to find 1 + r. So
![1 + r = \sqrt[5]{\frac{4617}{608}}](https://tex.z-dn.net/?f=1%20%2B%20r%20%3D%20%5Csqrt%5B5%5D%7B%5Cfrac%7B4617%7D%7B608%7D%7D)
So
The difference would be 0.27
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
I think the answer is y=23x+3....
Sorry if I get it wrong! Have a nice day! (:
