Answer:
20
Step-by-step explanation: you have to find the amount of change then determine the percent of increase and round it to the nearest percent
32 -56=24 then round to the nearest number you get 20
Answer:
14
Step-by-step explanation:
Given that:
Each fish bowl to have pebbles of weight equivalent to = 
Total pounds of pebbles that Timothy can use = 
To find:
The greatest value of Total number of fish bowls that Timothy can fill ?
Solution:
First of all, we need to convert mixed fraction into a fractional number and then we also need to see division of two fractions.
Formula:

Now, the given mixed fraction can be converted to fractional number as:

Now, To find the total number of fish bowls that can be filled, we need to divide the total number of pounds with number of pounds of pebbles in each fish bowl.
So, the answer is:

<em>14</em> number of fish bowls can be filled.
Answer:
a. 7.54385 in^2
Step-by-step explanation:
surface area equation = 3.14 * r^2
diameter is 2 times radius
x=3.14 (1.55^2)
x=7.54385 in^2
Answer:
Option C
Step-by-step explanation:
You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.
The total cost has to be in units of $.
There are two types of costs in the problem:
Those that depend on the number of days ($/day
)
Those that depend on the number of students and the number of days ($/(student * day))
If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'
So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:
3 days (Cost of training + Cost of food Miscellaneous expenses :).
Therefore the correct answer is option C:
C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.
The expression that represents the total expense should have a formula similar to this:
![y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars](https://tex.z-dn.net/?f=y%20%3D%20%283%20days%29%20%2A%28%5B%5Cfrac%7B20.dollars%7D%7B%28day%20%2A%20student%29%7D%20%2B%20%5Cfrac%7B30.dollars%7D%7B%28student%20%2A%20day%29%7D%20%2B%20%5Cfrac%7B50.dollars%7D%7B%28student%20%2A%20day%29%7D%5D%20b%20%2B%20%5Cfrac%7B200%7D%7Bday%7D%29%20%2B%201050.dollars)
y = 3 ($ 100b + $ 200) + $ 1050