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2 years ago

Plz help im almost of of time

Mathematics

2 answers:

harina [27]2 years ago

8 0

Answer:

2 and 1

Step-by-step explanation:

Basically divide the answer with what's being divided

tatuchka [14]2 years ago

4 0

Answer:

1. 9

2. 15

because you subtract exponents when dividing

Step-by-step explanation:

You might be interested in

Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T

Kaylis [27]

Answer:

z (max) = 1250 $

x₁ = 25 x₂ = 0 x₃ = 25

Step-by-step explanation:

Profit $ mach. 1 mach. 2

Product 1 ( x₁ ) 30 0.5 1

Product 2 ( x₂ ) 50 2 1

Product 3 ( x₃ ) 20 0.75 0.5

Machinne 1 require 2 operators

Machine 2 require 1 operator

Amaximum of 100 hours of labor available

Then Objective Function:

z = 30*x₁ + 50*x₂ + 20*x₃ to maximize

Constraints:

1.-Machine 1 hours available 40

In machine 1 L-H we will need

0.5*x₁ + 2*x₂ + 0.75*x₃ ≤ 40

2.-Machine 2 hours available 40

1*x₁ + 1*x₂ + 0.5*x₃ ≤ 40

3.-Labor-hours available 100

Machine 1 2*( 0.5*x₁ + 2*x₂ + 0.75*x₃ )

Machine 2 x₁ + x₂ + 0.5*x₃

Total labor-hours :

2*x₁ + 5*x₂ + 2*x₃ ≤ 100

4.- Production requirement:

x₁ ≤ 0.5 *( x₁ + x₂ + x₃ ) or 0.5*x₁ - 0.5*x₂ - 0.5*x₃ ≤ 0

5.-Production requirement:

x₃ ≥ 0,2 * ( x₁ + x₂ + x₃ ) or -0.2*x₁ - 0.2*x₂ + 0.8*x₃ ≥ 0

General constraints:

x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 all integers

The model is:

z = 30*x₁ + 50*x₂ + 20*x₃ to maximize

Subject to:

0.5*x₁ + 2*x₂ + 0.75*x₃ ≤ 40

1*x₁ + 1*x₂ + 0.5*x₃ ≤ 40

2*x₁ + 5*x₂ + 2*x₃ ≤ 100

0.5*x₁ - 0.5*x₂ - 0.5*x₃ ≤ 0

-0.2*x₁ - 0.2*x₂ + 0.8*x₃ ≥ 0

x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max) = 1250 $

x₁ = 25 x₂ = 0 x₃ = 25

6 0

2 years ago

Given: cos α = 4/5, sin β= 4/5, and α and β are both in quadrant 1. find sin (α+β)

mezya [45]

We have the formula (sin x)^2 + (cos x)^2 = 1;
Then, sin α = $\sqrt{1- ( \frac{4}{5}) ^{2} } = \frac{3}{5} ;$
cos β = $\sqrt{1- ( \frac{4}{5}) ^{2} } = \frac{3}{5} ;$
We apply the formula sin ( α + β ) = sin α x cos β + sin β x cos α = (3/5)x(4/5) + (4/5)x(3/5) = 12/25 + 12/25 = 24/25;

8 0

3 years ago

Can anyone please help me to find the area of this please

valentinak56 [21]

9514 1404 393

Answer:

√35 +3√7 -6 . . . square units

Step-by-step explanation:

The area can be figured a number of ways. The figure can be divided into parts, and the areas of those parts added.

Or, the area of the enclosing rectangle can be found, and the rectangle at upper right that is not shaded can be subtracted from that. We choose the latter.

The overall width is the sum of the given partial widths:

width = (√7 -2) + (2) = √7

Then the area of the bounding rectangle is ...

A = LW = (√5 +3)(√7) = √35 +3√7

The area of the upper right empty-space is ...

A = LW = (3)(2) = 6

Then The area of the shaded figure is ...

√35 +3√7 -6

5 0

2 years ago

An amount of $35,000 is borrowed for 6 years at 4.5% interest, compounded annually. if the loan is paid in full at the end of th

Vlada [557]

Answer: $45579.10
35000(1+.045)^6
Hope this helps!!!!!!!!!!!!!!

3 0

3 years ago

4C. Quintin is using the three different shaped

Sauron [17]

The smallest number of tiles Quintin will need in order to tile his floor is 20

The given parameters;

number of different shapes of tiles available = 3

number of each shape = 5

area of each square shape tiles, A = 2000 cm²

length of the floor, L = 10 m = 1000 cm

width of the floor, W = 6 m = 600 cm

To find:

the smallest number of tiles Quintin will need in order to tile his floor

Among the three different shapes available, total area of one is calculated as;

$A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2$

Area of the floor is calculated as;

$A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2$

The maximum number tiles needed (this will be possible if only one shape type is used)

$maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number= 60$

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

$3 \times \ smallest \ number = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20$

Thus, the smallest number of tiles Quintin will need in order to tile his floor is 20

Learn more here: brainly.com/question/13877427

3 0

2 years ago