The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes = 

Distance covered by a scuba diver in 2.6 minutes = 

Rate of a scuba diver ascending for 2 minutes = 

Distance covered by a scuba diver in 2 minutes = 

The position of scuba diver after 4.6 minutes relative to sea level:

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
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[5(14-2)^2]/2=
(5•12^2)/2=
5•144/2=
5•72=
720/2= 360
Answer:
280
Step-by-step explanation:
what i did was just go step by step in what your teacher tells you to do but i am going to say this may be wrong.
Ok. <span>well the answer 1/2 the hour you paint 1/2 in 1/4 so add 1/2+1/2=1 so it is 2 so 1/4+1/4 </span>
No she doesn't have enough money. All you do is multiply 8.60 by .2 which come out to 1.72 and 8.60 plus 1.73 which equals 10.33 so she needs 33 more cents tone able to tip 20%.