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MAXImum [283]
3 years ago
6

Write an addition sentance to make 1/9 using 2 fractions

Mathematics
1 answer:
tatuchka [14]3 years ago
6 0
I don't know but you have to put the 1/9 differently
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Find the value of x<br><br>m&lt;2 = 9x - 1​
jasenka [17]

Answer: x=9

Step-by-step explanation:

The bottom triangle that has a 40° is an isosceles triangle, therefore the other angle at the bottom right is also 40°. This leaves the top angle to be 100°.

180=40+40+x

180=80+x

x=100

Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°

180-100=∠2

80°=∠2

The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.

80=9x-1

81=9x

x=9

8 0
3 years ago
Which of the binomials below is a factor of this trinomial?<br> x² - 4x - 12
marysya [2.9K]

Step-by-step explanation:

x2 - 4x - 12

Finding factors of 12 then

x2 - 6x + 2x - 12

x( x - 6) + 2 (x - 6)

So the factors are (x+2) (x-6)

7 0
3 years ago
If ef bisects angle ceb,angle cef=7x+31 and angle feb=10x-3
Nastasia [14]

Given : Angle  < CEB is bisected by EF.

< CEF = 7x +31.

< FEB = 10x-3.

We need to find the values of x and measure of < FEB, < CEF  and < CEB.

Solution: Angle  < CEB is bisected into two angles < FEB and < CEF.

Therefore,   < FEB = < CEF.

Substituting the values of < FEB and < CEF, we get

10x -3 = 7x +31

Adding 3 on both sides, we get

10x -3+3 = 7x +31+3.

10x = 7x + 34

Subtracting 7x from both sides, we get

10x-7x = 7x-7x +34.

3x = 34.

Dividing both sides by 3, we get

x= 11.33.

Plugging value of x=11.33 in < CEF = 7x +31.

We get

< CEF = 7(11.33) +31 =  79.33+31 = 110.33.

< FEB  = < CEF =  110.33 approximately

< CEB = < FEB +  < CEF  = 110.33 +110.33 = 220.66 approximately



7 0
3 years ago
50 points answer asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vovikov84 [41]

Answer:

2,568.39ft2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Of 734 students, 442 are taking mathematics. What angle (in degrees) of a circle would show the percent of students taking mathe
Anestetic [448]

We need to find the angle (rounded to the nearest whole degree) of a circle that would represent the percent of students taking mathematics.

Since a complete turn around the circle has 360º, we have the following proportion:

<em>Number of students Angle</em>

734 360º

442 x

Then, cross multiplying the above values, we obtain:

\begin{gathered} 734x=442\cdot360\degree \\  \\ x=\frac{442\cdot360\degree}{734} \\  \\ x\cong217\degree \end{gathered}

<em>Answer</em>: 217º

6 0
1 year ago
Read 2 more answers
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