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guajiro [1.7K]
3 years ago
6

A family has two cars. The first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of

20 miles per gallon of gas. During one particular week, the two cars went a combined total of 2000 miles, for a total gas consumption of 70 gallons. How many gallons were consumed by each of the two cars that week?
Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Let x = gallons consumed by car 1

Let y = gallons consumed by car 2

We set up our equations:

35x+40y = 1850 eq1

x+y = 50 eq2

Substituting eq 2 into eq 1,

35x+40(50-x) = 1850

35x+2000-40x = 1850

-5x+2000 = 1850

-5x = -150

x = 30

Substitute value of x into eq 2.

x+y = 50

30+y = 50

y = 20

Car 1 consumes 30 gallons of gas.

Car 2 consumes 20 gallons of gas.

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Answer:

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\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

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M = 1.96\frac{0.000586}{\sqrt{59}} = 0.0002

The lower end of the interval is the sample mean subtracted by M. So it is 0.2905 - 0.0002 = 0.2903 mm

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4 0
3 years ago
Round 45.587 to the nearest hundredth
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replace A with 0.13P and t with 400


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divide both sides by P
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multiply both sides by k
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divide oth sides by ln0.13
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