Hi there!
∠C = 40° and triangle ABC is isosceles, therefore:
∠C = ∠A = 40°
Angles in a triangle sum up to 180°, so:
180 = 40 + 40 + ∠A
180 = 80 + ∠A
100 = ∠A
Thus, arc CB has a measure of 100°.
What's all the answers so I can figure it out which answer it would be?
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Answer:
5(√3 - 1)
Step-by-step explanation:
Edge of cube = 10
If the sphere is inscribed in a cube, the edges of the cube is equal to the diameter of the sphere.
Diameter = 10
We will then find the diagonal of the cube.
Diagonal = √10^2 + 10^2 + 10^2
= √300
= 10√3
Let X be the distance between the vertex of the cube and the surface of the sphere
X = (diagonal - diameter) /2
X = (10√3 - 10)/2
X = (10(√3 - 1))/2
X = 5(√3 - 1)
Its not really hard you just have to explain when like its not really complicated
