All categories

2 years ago

4x+5/6 = 7/2 solve for x

Mathematics

1 answer:

n200080 [17]2 years ago

4 0

Answer:

4x=7/2-5/6

4x=21-5/6

4x=16/6

x=8/12

x=2/3

x=0.6666.....

You might be interested in

Select all the points that are on the graph of the equation 4y - 6X equals 12

liraira [26]

Answer:

4ieideerriiiriiieeoeoeoee

7 0

3 years ago

Given that f(x) = x2 + 12x + 32 and g(x) = x+ 4, find (f - g)(x) and

frosja888 [35]

Answer:

x²+11x+28

Step-by-step explanation:

(f - g) (x) = f(x) - g(x)

x² + 12x + 32 - (x + 4) = x² + 11x + 28

6 0

2 years ago

In a survey of 400 randomly selected people, it was determined that 22 play soccer. What is the probability that a randomly sel

insens350 [35]

Answer:

5.5% probability that a randomly selected person plays soccer

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

People surveyed who play soccer, so $D = 22$

Total outcomes:

Total people surveyed, so $P = 400$

What is the probability that a randomly selected person plays soccer?

$P = \frac{D}{T} = \frac{22}{400} = 0.055$

5.5% probability that a randomly selected person plays soccer

6 0

3 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$