Answer:
10 cm
Step-by-step explanation:
im smart
Answer:

Step-by-step explanation:
The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.
Thus, since John already knows that
and
, therefore, an additional information showing that the angle between
and
in ∆ABC is congruent to the angle between
and
in ∆DEF.
For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be
.
See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.
Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC
Answer:
Yes.
Step-by-step explanation:
Yes, it is possible. For example, 0.2 and 0.2 both have one decimal place and one significant digit. Their product, 0.04, has one significant digit, but has 2 decimal places.