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Ratling [72]
2 years ago
6

According to the figure given here,

Mathematics
2 answers:
AfilCa [17]2 years ago
4 0

Answer:

(i) 90°

(ii) CÔD

(iii) AÔD = 110°

(iv) 180°

(v) AÔD

(vi) AÔB

Step-by-step explanation:

Two angles are said to be complementary if they add up to 90°.

Complementary angles can either be adjacent or non-adjacent.

Two Angles are said to be supplementary if they add up to 180°.

Complementary angles can either be adjacent or non-adjacent.

(i) BÔC + CÔD = 25 + 65 = 90°

(ii) BÔC = 25°

Therefore the complementary angle measures 90 - 25 = 65°

So the complement of BÔC is CÔD

(iii) AÔD = 20 + 25 + 65 = 110°

(iv) AÔD + DÔE = 110 + 70 = 180°

(v) DÔE = 70°

Therefore the supplementary angle measures 180 - 70 = 110°

So the supplement of DÔE is AÔD

(vi) DÔE = 70°

Therefore the complementary angle measures 90 - 70 = 20°

So the complement of DÔE is AÔB

Readme [11.4K]2 years ago
4 0

#1

  • <BOC+<COD=25+65=90

#2

Let the complement be x

  • x=90-25=75

#3

  • <AOD=20+25+65=110

#4

  • <AoD+<DOE=110+70=180°

#5

  • x=90-70=20
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\dfrac{BN}{CN}=\dfrac{3}{5}

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\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,

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Consider triangles ACB and PCN. In these triangles,

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Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,

so

\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}

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