In addition to mean and sample size you will need the individual scores.
The formula for standard deviation is:
S^2 = E(X-M)^2/N-1
Here's an example:
Data set: 4,4,3,1
Mean: 3
Sample size: 4
First, put the individual scores one after the other and subtract the mean from it.
4 - 3 = 1
4 - 3 = 1
3 - 3 = 0
1 - 3 = -2
Second, square the answers you got from step 1.
1^2 = 1
1^2 = 1
0^2 = 0
-2^2 = 4
Third, plug the values from step 2 into the formula.
S^2 = (1+1+0+4)/(4-1) = 6/3 = 2
Standard deviation = 2
Answer:
<h3>No, it is not a right triangle</h3>
Step-by-step explanation:
In order to know whether the triangle is a right angle, we need to show that the square of the longest side is equal to the sum of the square of the other two sides
Longest side = 17in
other two sides = 8in and 9in
Check:
17² = 289
Sum of the square of other two sides
= 8² +9²
= 64 + 81
= 145
Since 17² ≠ 8² +9², hence the triangle that Landon created is not a right triangle
Answer:
We should expect <u>10 iris bouquet</u> will be sold out of next 35 bouquet sold.
Step-by-step explanation:
Given;
Number of iris bouquets sold yesterday = 6
Number of other bouquets sold yesterday = 15
We need to find number of iris bouquets sold out of 35 bouquets sold.
Solution:
First we will find the percent of iris bouquet sold yesterday.
Now we know that;
Total bouquet sold yesterday is equal to sum of Number of iris bouquets sold yesterday and Number of other bouquets sold yesterday.
framing in equation form we get;
Total bouquet sold yesterday = 
Now we can say that;
Percent of iris bouquet sold is equal to Number of iris bouquets sold yesterday divided by Total bouquet sold yesterday and then multiplied by 100
framing in equation form we get;
Percent of iris bouquet sold = 
Now based on this data we need to find number of iris bouquet sold when total bouquet sold is 35.
number of iris bouquet = 
Hence we should expect <u>10 iris bouquet</u> will be sold out of next 35 bouquet sold.
Answer:
Step-by-step explanation:
Thank you for providing the details of the question.
Unfortunately none of the results you have to choose from will give you 44%
The problem resembles the first probability question you were likely asked. "What is the probability of getting a heads on every throw of a fair coin?" The answer is 1/2 no matter how many times you throw the coin or what has happened before any point in the throws.
The answer should be 6/50. If this turns out not to be the answer and you have an instructor your safest course of action is to ask how 44% was obtained. Tell me in a comment.
Answer: 5
Step-by-step explanation:
