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2 years ago

A user can easily move to the end of a document by pressing the _____ key combination.

Computers and Technology

2 answers:

Svetach [21]2 years ago

7 0

Answer: Ctrl+End

Explanation:

Ctrl+End is the key shortcut used from keyboard for coming to end of any document , text or page. This key combination is also known as end key.

Other options are incorrect because Ctrl+down arrow is key combination for moving the paragraph or text downwards.

Ctrl+E is the shortcut that can refer different meanings in different context such as Microsoft Powerpoint , internet browser etc.

Alt+End key is defined for tables to come to last element in Microsoft Word Table.

Thus, the correct option is option Ctrl +End.

stiv31 [10]2 years ago

4 0

Ctrl + End

Crtl + E brings you to the search bar as if you wanted to search something quickly

Crtl + Down Arrow does nothing

Alt + End does nothing as well (with my understanding)

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Create a new Die object. (Refer to Die.html for documentation.)Create a loop that will iterate at least 100 times. In the loop b

hjlf

Answer:

Java code is given below

Explanation:

import java.util.Random;

class Die{

private int sides;

public Die(){

sides = 6;

}

public Die(int s){

sides = s;

}

public int Roll(){

Random r = new Random();

return r.nextInt(6)+1;

}

class DieRoll{

public static void main(String[] args) {

Die die = new Die();

int arr[] = new int[6];

for(int i=0; i<6; i++)

arr[i] = 0;

for(int i=0; i<100; i++){

int r = die.Roll();

arr[r-1]++;

}

for(int i=0; i<6; i++)

System.out.println((i+1)+" was rolled "+arr[i]+" times.");

}

8 0

3 years ago

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

$v = \frac{(xf-xo)}{(t-to)}$