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solmaris [256]
3 years ago
10

A user can easily move to the end of a document by pressing the _____ key combination.

Computers and Technology
2 answers:
Svetach [21]3 years ago
7 0

Answer: Ctrl+End

Explanation:

  • Ctrl+End is the key shortcut used from keyboard for coming to end of any document , text or page. This key combination is also known as end key.
  • Other options are incorrect because Ctrl+down arrow is key combination for moving the paragraph or text downwards.
  • Ctrl+E is the shortcut that can refer different meanings in different context such as Microsoft Powerpoint , internet browser etc.
  • Alt+End key is defined for tables to come to last element in Microsoft Word Table.
  • Thus, the correct option is option Ctrl +End.

stiv31 [10]3 years ago
4 0

Ctrl + End

Crtl + E brings you to the search bar as if you wanted to search something quickly

Crtl + Down Arrow does nothing

Alt + End does nothing as well (with my understanding)

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Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

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Answer:

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The correct answer is "opinion".

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3 years ago
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