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WITCHER [35]
3 years ago
6

The sum of two numbers is 48. If one third of one number is 5 greater than one sixth of another number, which of the following i

s the smaller number?
a. 6
b. 26
c. 22
d. 42
Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0
<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a = 
a = 26
then
26 + b = 48
b = 48 - 26

b = 22</span>
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Answer:

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p(x) = x(1 - \frac{15}{100}) = 0.85x

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where x is the discounted price.

Therefore, the composite function that gives the total cost of the riding lawn mower on sale is given by

(t o p)(x) = 1.065(0.85x) = 0.9x ............ (1)

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(t o p)(3000) = 0.9 × 3000 = 2700 dollars. (Answer)

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3 years ago
What is the measure of angle TSU?​
goldfiish [28.3K]

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80

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7 0
3 years ago
Is 0.09 squared a rational number?
Novay_Z [31]
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7 0
3 years ago
1. The difference of two numbers is 3, and the sum of three times the larger one and
vlada-n [284]

Answer: 25 and 22

Step-by-step explanation:

Since one number is 3 bigger than the other, we can call them x, and x-3.

Then we know that the sum of 3 times x and 2 times (x-3) is equal to 19, so we can make the equation

3x+2(x-3)=19

Simplifying would get you

3x+2x-6=19

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5x = 25

divide by 5 and

x=5

Put those numbers back into your previous labels for them, x and x-3, and you get 5 and 2

Hope this helps

5 0
3 years ago
Sarah has 284 coins in a piggy bank with a total value of $22.78. Sarah has 173 pennies, 5 more dimes than nickels, the rest are
pickupchik [31]
Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)

a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1)  N + D + Q = 111 coins

b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins

c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:

(1)  N + D + Q = 111 coins
(2) D - N = 5 coins
(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
17 coins N ( x 5 = 85 cents)
22 coins D ( x 10 = 220 cents)
72 coins D ( x 25 = 1,800 cents)
and 173 P,
proof:
that makes a total of 85+2201800+172 =2,278 c or $22.78




7 0
3 years ago
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