Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
x = 4
Step-by-step explanation:
(8)(7) = 14x
14x = 56
20 5/8
here u gooooo that's the answer
