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Xelga [282]
3 years ago
7

Lana's family is planning a rectangular garden. They make a scale diagram of the garden using a scale of 1 inch to 0.5 meter. If

the length of the scale diagram is 24 inches, and its width is 16 inches, what is the perimeter of the actual garden? Please help me with this question.
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
So, when you find a perimeter, you add length+length+width+width= perimeter.So in your case, it would be 24 x 2 since there are 2 sides, and 16 x 2, then add the results. 48 + 32 = 80 inches. then convert to meters.
ozzi3 years ago
4 0
12 by 8 ft. :) If you multiply the perimeter is 96. I hope this helps!
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Number between 3.45 and 3.46
GenaCL600 [577]

Answer:

3.451, 3.452, 3.453, 3.454, 3.455, 3.456, 3.457, 3.458, 3.459, 3.460

4 0
3 years ago
Large takes a square piece of cardboard and cut for it by 4 inch squares out of each corner because the sides up to make a box w
chubhunter [2.5K]
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3 years ago
Find the discriminant of 3x^2-10x=-2
Oksanka [162]

Answer:

76

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

then the discriminant is Δ = b² - 4ac

given 3x² - 10x = - 2 ( add 2 to both sides )

3x² - 10x + 2 = 0 ← in standard form

with a = 3, b = - 10 and c = 2

b² - 4ac = (- 10)² - (4 × 3 × 2) = 100 - 24 = 76


7 0
3 years ago
Suppose that f: R --> R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
3 years ago
What is the value of the expression below?
lozanna [386]

Answer:

25x10^18/4   or    6.25x10^18

Step-by-step explanation:

2.5x10^33x5x10^-15/2

12.5x10^18/2

6 0
3 years ago
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