1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
3 years ago
12

jada goes to get her hair done the cost for a haircut and blowout is 65.42 she leaves a 25% tip for the stylist what is the tota

l
Mathematics
2 answers:
Art [367]3 years ago
4 0

Answer:

The total cost is $81.78

Step-by-step explanation:

First lets calculate the tip

tip = cost * percent of tip

tip = 65.42*.25

tip = 16.355

Which rounds to 16.36  since we are working with money and round to the nearest cent

total cost = cost of cut and blowout + tip

                = 65.42 +16.36

                     =81.78

mamaluj [8]3 years ago
4 0
$81.78
first you have to multiple 25%( or 0.25 ) to $65.42 and that will give you the tax #. Then you add $16.36 (tax #) to $65.42 then you get your total.

$65.42 x 0.25= $16.36
$16.36 + $65.42= $81.78
You might be interested in
Plz i need help soon
lana66690 [7]
The answer is C. It has the wrong graph labels.
7 0
3 years ago
Complete the table above.
4vir4ik [10]

\bf \begin{array}{|c|c|c|ll}
\cline{1-3}
x&y=3x^2&y=3^x\\
\cline{1-3}&&\\
0&\stackrel{3(0)^2}{0}&\stackrel{3^0}{1}\\&&\\
1&\stackrel{3(1)^2}{3}&\stackrel{3^1}{3}\\&&\\
2&\stackrel{3(2)^2}{12}&\stackrel{3^2}{9}\\&&\\
\cline{1-3}
\end{array}

4 0
3 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
3 years ago
Claire has 38 yards of material to make costumes for the school play.
NemiM [27]

Answer:

16

Step-by-step explanation:

38 divided by 2 3/8 is 16 and 16 times 2 3/8 is 38

3 0
2 years ago
How can you tell the difference between the
kolbaska11 [484]

Answer:

Step-by-step explanation:

A coefficent is the number in front of the letter and a constant is just a number

5 0
3 years ago
Read 2 more answers
Other questions:
  • Find a the coordinate of the midpoint M given the two endpoints
    12·2 answers
  • The company you work for has a policy of paying overtime for all hours worked in excess of 40 per week you worked 8 hours each d
    14·1 answer
  • Find (f ∘ g)(4) when f(x) = -5x - 7 and g(x) = -6x 2 + 9x + 9.
    5·1 answer
  • Which score is better in terms of percentages: 12 out of 15 or 23 out of 26?
    9·1 answer
  • Will give brainliest.
    8·1 answer
  • What is the constant of proportionality of the following equation?<br> B = 1.25C
    7·2 answers
  • The monthly utility bills in a city are normally distributed with a mean of $100 and a standard deviation of $12. Find the proba
    11·1 answer
  • I NEED HELP!! WITH NUMBER 4 BOTH ANSWERS
    10·2 answers
  • PLEASE HELP!!! give an explanation if you can
    10·1 answer
  • GCSE MATHS PLEASE HELP
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!