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Ugo [173]
3 years ago
6

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It

is believed that the machine is underfilling the bags. A 40 bag sample had a mean of 429.0 grams. A level of significance of 0.05 will be used. Is there sufficient evidence to support the claim that the bags are underfilled? Assume the standard deviation is known to be 23.0. What is the conclusion?
Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

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Answer:

The result is 150 + 1.5d

Step-by-step explanation:

We want to translate the wordings into algebraic expression.

Firstly, we increase 120 by d%

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So increasing 120 by d % means;

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Then increase this by 25%

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