Mr. Moore's physics class built different-shaped parachutes to see which shapes were more effective. The students tested the par
achutes by dropping them
from a height of 30 feet and timing the fall. They calculated the summary below:
The students wanted to see what happens to their times when they drop the parachutes from 45 feet. They find that every drop is increased by 2.5 seconds.
Find the new mean and standard deviation.
O Mean, 3.1 seconds; standard deviation, 0.6 second
O Mean, 5.6 seconds; standard deviation, 3.1 seconds
O Mean, 5.6 seconds; standard deviation, -1.9 seconds
O Mean, 8.1 seconds, standard deviation, 0.6 second
from a height of 30 feet and timing the fall. They calculated the summary below:
The students wanted to see what happens to their times when they drop the parachutes from 45 feet. They find that every drop is increased by 2.5 seconds.
Find the new mean and standard deviation.
O Mean, 3.1 seconds; standard deviation, 0.6 second
O Mean, 5.6 seconds; standard deviation, 3.1 seconds
O Mean, 5.6 seconds; standard deviation, -1.9 seconds
O Mean, 8.1 seconds, standard deviation, 0.6 second
1 answer:
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624/27
first you have to know what number that can be subtracted by 62
1. do 27 times 2 equal 54 then you subtract 62 by 54 equal 8 then you put 84 together that will 84 then multiply 27 times 3 = 81 then subtracted by 84
84-81 equal 3
In the calculator the answer is 23.1111111111