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Hatshy [7]
3 years ago
14

At the end of the year a car is worth 5% less than what it was worth at the beginning of the year. If a car was worth $9 500 in

December 2016, then its value in January 2016 was

Mathematics
2 answers:
motikmotik3 years ago
6 0

Answer:

that is the correct solution to the question

Pepsi [2]3 years ago
3 0
The answer should be 9025
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Simplify: √8x^5+ x√18x^3<br>÷x^2√50x​
Sergeu [11.5K]

Answer:

10x^2 √2x

Step-by-step explanation:

hope this helps

lmk if it's wrong

7 0
2 years ago
Describe the graph of of the equation x = -2. Is the equation a function?
Cloud [144]
In the event that a line has no y-intercept, that implies it never converges the y-intercept, so it must be parallel to the y-intercept. This implies it is a vertical line, for example, . This slant of this line is vague. In the event that the line has no x-intercept, at that point it never meets the x-intercept, so it must be parallel to the x-pivot. 

If x-intercept is -2 the line would be vertical as the y-intercept = 0. 


7 0
2 years ago
Read 2 more answers
How to do this does anyone know if u do i will make u brainlist
Studentka2010 [4]

Answer:

Those functions are for a graph.

Step-by-step explanation:

You can compare them by heading to a website like desmos and plugging in each function, I think they even do tables as well.

These are functions that can be graphed, I assume you know what that is, if not, look it up.

good luck

6 0
1 year ago
Read 2 more answers
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}&#10;term&value\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;a_1&-4096\\&#10;a_2&-4096r\\&#10;a_3&-4096rr\\&#10;a_4&-4096rrr\\&#10;&-4096r^3\\&#10;&64&#10;\end{array}\implies -4096r^3=64&#10;\\\\\\&#10;r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}&#10;\\\\\\&#10;r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\&#10;-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;r=-\frac{1}{4}\\&#10;a_1=-4096\\&#10;n=6&#10;\end{cases}&#10;\\\\\\&#10;a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
2 years ago
Read 2 more answers
Please can someone answer this.
ivanzaharov [21]

Answer:

  •  x = -4, x = 0, x = 1

Step-by-step explanation:

x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)

The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)

Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.

___

Of course, your graphing calculator can answer this almost as quickly.

7 0
3 years ago
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