Answer:
Step-by-step explanation:

b.
an=an-1+3
C.
when x=15
y=3×15-2=45-2=43
a15=43
The probability of 1 number showing up out of 20 is 1/20
The probability of 3 different numbers showing up would be 3/20
Answer: 3/20
Answer:
The scale reading that the chef need to see for this spice when preparing the specialty for 43 people is 0.86.
Step-by-step explanation:
In order to find the answer, you need to multiply the amount that the chef uses per serving for the number of servings. The statement indicates that the chef uses one- fiftieth of an ounce of a spice per serving and this is represented as 1/50 and you have to multiply this for 43 that is the number of people.
You can find 1/50 as a decimal dividing 1 by 50:
1/50=0.02
Now, you can multiply this value for 43:
0.02=43=0.86
According to this, the answer is that the scale reading that the chef need to see for this spice when preparing the specialty for 43 people is 0.86.
Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:

Rewrite the integrand:

The integral is then
