So to answer this problem you would need to set up an equation as the original price and the 15% percent of the original price is unknown. If x is the original price then x + 15% of the original price will equal 4623.
x+ .15x=4623
Combine the like terms
1.15x=4623
Solve
x=4020
The answer is the last one
Answer:
h(1)=-13
![h(n)=h(n-1)-13, n\geq 2](https://tex.z-dn.net/?f=h%28n%29%3Dh%28n-1%29-13%2C%20n%5Cgeq%202)
Step-by-step explanation:
We are given that
![h(n)=-13n](https://tex.z-dn.net/?f=h%28n%29%3D-13n)
We have to find the recursive formula of h(n).
Substitute n=1
![h(1)=-13](https://tex.z-dn.net/?f=h%281%29%3D-13)
n=2
![h(2)=-13-13=-26=h(1)-13](https://tex.z-dn.net/?f=h%282%29%3D-13-13%3D-26%3Dh%281%29-13)
n=3
![h(3)=-13(3)=-39=-26-13=h(2)-13](https://tex.z-dn.net/?f=h%283%29%3D-13%283%29%3D-39%3D-26-13%3Dh%282%29-13)
![h(4)=-13(4)=-52=-39-13=h(3)-13](https://tex.z-dn.net/?f=h%284%29%3D-13%284%29%3D-52%3D-39-13%3Dh%283%29-13)
:
:
:
![h(n)=h(n-1)-13](https://tex.z-dn.net/?f=h%28n%29%3Dh%28n-1%29-13)
Therefore, the recursive formula is given by
h(1)=-13
![h(n)=h(n-1)-13, n\geq 2](https://tex.z-dn.net/?f=h%28n%29%3Dh%28n-1%29-13%2C%20n%5Cgeq%202)
Answer:
They're all right
Step-by-step explanation:
When you have a negative exponent, you take the reciprocal of it so it becomes positive.
ANSWER
![x = \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
EXPLANATION
The given exponential equation is
![{9}^{x + 1} = 27](https://tex.z-dn.net/?f=%20%7B9%7D%5E%7Bx%20%2B%201%7D%20%20%3D%2027)
The greatest common factor of 9 and 27 is 3.
We rewrite the each side of the equation to base 3.
![{3}^{2(x + 1)} = {3}^{3}](https://tex.z-dn.net/?f=%7B3%7D%5E%7B2%28x%20%2B%201%29%7D%20%20%3D%20%20%7B3%7D%5E%7B3%7D%20)
Since the bases are equal, we can equate the exponents.
![2(x + 1) = 3](https://tex.z-dn.net/?f=2%28x%20%2B%201%29%20%3D%203)
Expand the parenthesis to get:
![2x + 2 = 3](https://tex.z-dn.net/?f=2x%20%2B%202%20%3D%203)
Group similar terms
![2x = 3 - 2](https://tex.z-dn.net/?f=2x%20%3D%203%20-%202)
![2x = 1](https://tex.z-dn.net/?f=2x%20%3D%201)
![x = \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)