Answer:
6. 550
7. 70
Step-by-step explanation:
6. 16+28 = 44, 44*25 = 1100 divided by 2 = 550
7. 2.5+3+5.5 = 11, 11+3 = 14, 14*10 = 140 divided by 2 = 70
 
        
             
        
        
        
Answer:
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
  
Where 
 and 
Since the distribution for X is normal then the  we know that the distribution for the sample mean 
 is given by:
And the standard error is given by:

Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  
Solution to the problem
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
  
Where 
 and 
Since the distribution for X is normal then the  we know that the distribution for the sample mean 
 is given by:
And the standard error is given by:

 
        
             
        
        
        
Answer: 4 years
Step-by-step explanation:
A(0) has to be amount at start. Assume that's 5mg
Then A(t) = 5×(0.5)^(0.25t) = 5×2^(-t/4),
(also known as 5 exp(-λ t) with λ = ln(2)/4, incidentally).
We need to such that A(t) = 2.5mg, or 2^(-t/4) is 1/2, which happens when -t/4 is -1, or t is 4.
 
        
             
        
        
        
Answer:
(1,-4) is in quadrant IV.
Step-by-step explanation:
 
        
             
        
        
        
Answer: 81
Step-by-step explanation: The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average. Write all of the numbers and cross out a even amount of numbers on both sides. Image 1 shows your problem. If your problem had another number, you solve it differently. Check image 2.