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avanturin [10]
3 years ago
15

Solve for x..................

Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0
7x - 9 < 12
7x < 12 + 9
7x < 21
x < 21/7
x < 3

1/4x + 8 > 11
1/4x > 11 - 8
1/4x > 3
x > 3 * 4
x > 12

solution : x < 3 or x > 12
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Step-by-step explanation:

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fgiga [73]

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Step-by-step explanation:

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7 0
3 years ago
Find the value of x L 7x-7 M 4x+14
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Step-by-step explanation:

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8 0
3 years ago
Solve the equation 3 - 4-587<br> 3.87<br> b. 0.55, -0.55<br> a.<br> C. 1.53,-1.53<br> d. 4.98
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8 0
3 years ago
Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

6 0
3 years ago
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