The rhombus always has perpendicular diagonals.
Answer:
yes 6/5 is greater
Problem solving:
first you need to simply the fractions and see which one is bigger.
2/3 = 0.667
6/5 = 1.2
<em />
<em>-Sumin <3</em>
If the stretch is proportional to the weight, it will satisfy
weight/(49 cm) = (135 N)/(21 cm)
weight = (49/21)×135 N
weight = 315 N
The weight of the fish would be 315 N.
Answer:
(C) -7x − 5y = -48
Step-by-step explanation:
We look for the equation of the line AB
We have then:
y-yo = m (x-x0)
m = (y2-y1) / (x2-x1)
m = (4 - (- 1)) / (4 - (- 3))
m = 5/7
We choose an ordered pair:
(xo, yo) = (4, 4)
Substituting:
y-4 = (5/7) (x-4)
y = (5/7) x-20/7 + 4
7y = 5x - 20 + 28
7y = 5x + 8
y = (5/7) x + 8/7
The equation of the perpendicular line is:
-7x - 5y = -48
Answer:
the equation of BC is:
(C) -7x - 5y = -48
