6% or 0.06 is the simple interest rate the bank pays him.
<u>Step-by-step explanation:</u>
Sir Ving Spoon earned $5,436 on his $7,550 certificate of deposit.
From this given information,
It can be determined that the Principal amount is $7550 and the interest amount is $5436.
The CD is for 12 years. Therefore, the number of years is 12.
<u>To find the interest rate (r) :</u>
Using the simple interest formula,
Interest = P×r×t
where,
- P is the principal amount = $7550
- r is the rate of interest.
- t is the number of years = 12
⇒ 5436 = 7550 × r × 12
⇒ 5436 = 90600 × r
⇒ r = 5436 / 90600
⇒ r = 0.06
Multiply by 100 to represent in rate %
⇒ r = 0.06 × 100
⇒ r = 6%
∴ 6% or 0.06 is the simple interest rate the bank pays him.
Answer:
(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)
Step-by-step explanation:
Factor all the expressions,
1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)
2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)
3rd expression=2x^2 + x - 21=(x - 3) (2 x + 7)
HCF=Commo factor=(x-3)
LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)
Answer:
a) ![f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000](https://tex.z-dn.net/?f=f%28t%29%3D0.001155%5B%5Cfrac%7B2%7D%7B3%7Dt%28t-1980%29%5E%7B3%2F2%7D-%5Cfrac%7B4%7D%7B15%7D%28t-1980%29%5E%7B5%2F2%7D%5D%2B264%2C034%2C000)
b) f(t=2015) = 264,034,317.7
Step-by-step explanation:
The rate of change in the number of hospital outpatient visits, in millions, is given by:
a) To find the function f(t) you integrate f(t):
![\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt](https://tex.z-dn.net/?f=%5Cint%20%5Cfrac%7Bdf%28t%29%7D%7Bdt%7Ddt%3Df%28t%29%3D%5Cint%20%5B0.001155t%28t-1980%29%5E%7B0.5%7D%5Ddt)
To solve the integral you use:
Next, you replace in the integral:
Then, the function f(t) is:
![f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'](https://tex.z-dn.net/?f=f%28t%29%3D0.001155%5B%5Cfrac%7B2%7D%7B3%7Dt%28t-1980%29%5E%7B3%2F2%7D-%5Cfrac%7B4%7D%7B15%7D%28t-1980%29%5E%7B5%2F2%7D%5D%2BC%27)
The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.
Hence C' = 264,034,000
The function is:
b) For t = 2015 you have:
![f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7](https://tex.z-dn.net/?f=f%28t%3D2015%29%3D0.001155%5B%5Cfrac%7B2%7D%7B3%7D%282015%29%282015-1980%29%5E%7B1%2F2%7D-%5Cfrac%7B4%7D%7B15%7D%282015-1980%29%5E%7B5%2F2%7D%5D%2B264%2C034%2C000%5C%5C%5C%5Cf%28t%3D2015%29%3D264%2C034%2C317.7)
<h2>
Explanation:</h2>
We use an equation to say that two things are equal. An equation always has an equal sign "=". So an equation tells us that the left side is equal to the right side. In this case, we have the following equation:
So the only value that makes this equation to be true is 5, because:
For instance, let's choose another value, say, 8. So substituting:
If you already have 4% then that means that the other 48 grams is 96%.
So if you make a proportion with 96/100 and 48/x (x being a stand-in for the answer) you can cross multiply 48 and 100 and divide the end result by 96, which equals 50.
So that means that the answer is 50 grams of protein. Hope this helped!
