Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,
p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
The original number has to decimal places .25 so you would round to the 2 places I believe so 39.06
Answer:
Equation of tangent line at point (1,0) to given function is
y=x-1
Step-by-step explanation:
Equation of tangent line is
y-y₁=m(x-x₁)-----(1)
where m is slope of line and can be found by implicitly differentiating the given function w.r.to x
which is slope of tangent line. At (1,0) equation of tangent line is
0.6g=54
Explanation is in image hope this helps
Ok I can do that tomorrow but ok ok thank y’all for a good day ok ok thanks for your prayers I’ll talk to you tomorrow love love y’all are ok bye ok thanks man I have you come over for me some day you
