2 is less than 3x be the c in three and be big once you times the x number
The solution is greater than one but less than or equal to 8.
Hey there!
Line passes through (4, -1) & is parallel to 2x -3y=9
Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.
The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.
Start off by subtracting 2x from both sides.
-3y = -2x + 9
Then, divide both sides by -3.
y = (-2x + 9)/-3
Simplify.
y = 2/3x - 3
"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.
We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.
Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).
y-y₁=m(x-x₁)
Let's start by plugging in 2/3 for m (our new slope), 4 for x1 and -1 for y1.
y - (-1) = 2/3(x - 4)
Simplify.
y + 1 = 2/3 + 8/3
Simplify by subtracting 1 from both sides.
y = 2/3x + 8/3 - 1
Simplify.
y = 2/3x + 5/3
~Hope I helped!~
The sum of the function will be (r – s)(x) = –2x² + x – 3, The difference of the function will be (r – s)(x) = –2x² + x – 3, and The product of the function will be (r × s)(x) = 2x³ – 6x².
The complete question is attached below.
<h3>What is Algebra?</h3>
The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
The functions are given below.
r(x) = x – 3
s(x) = 2x²
The sum of the function will be
(r + s)(x) = x – 3 + 2x²
(r + s)(x) = 2x² + x – 3
The difference of the function will be
(r – s)(x) = (x – 3) – 2x²
(r – s)(x) = –2x² + x – 3
The product of the function will be
(r × s)(x) = (x – 3) (2x²)
(r × s)(x) = 2x³ – 6x²
More about the Algebra link is given below.
brainly.com/question/953809
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So you're initial equation is

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