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ad-work [718]
3 years ago
13

70 cm is what percent of a meter?

Mathematics
2 answers:
Brut [27]3 years ago
5 0
Since 100 cm's = 1 meter, 70 cm's = 70%.
leonid [27]3 years ago
3 0
1 meter is 100 cm so that means 70 cm is 70% of a meter
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Lakeridge health oshawa is a 423 beds hospital with 463 doctors and 4058 staff comprised of nurses and technologists. it is plan
Bezzdna [24]

The number of doctors that would be needed for the 35-bed wing is 38.

<h3>How many more doctors are needed?</h3>

The first step is to determine the number of doctors needed for one bed : 463 / 423

The second step is to multiply the ratio gotten in the first step by the number of beds in the new wing: (463 / 423) x 35 = 38.21 = 38

To learn more about ratios, please check: brainly.com/question/9194979

#SPJ1

3 0
2 years ago
Which expression can be used to find the area of the rectangle shown on the coordinate plane?
Naily [24]
Answer:

8 * 7

Explanation:

When you count the squares along the area, you will find that the base is 8 units, and the height is 7 units. The area of a square is equal to base * height, so the correct answer is 8 * 7.
7 0
3 years ago
Read 2 more answers
BRAINLIEST PLEASE HELP np<br> If f(x)=-x^2+6x-1 and g(x)=3x^2-4x-1, find (f+g)(x)
raketka [301]

Answer:

\large\boxed{B.\ (f+g)(x)=2x^2+2x-2}

Step-by-step explanation:

f(x)=-x^2+6x-1\\\\g(x)=3x^2-4x-1\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute:}\\\\(f+g)(x)=(-x^2+6x-1)+(3x^2-4x-1)\\\\(f+g)(x)=-x^2+6x-1+3x^2-4x-1\qquad\text{combine like terms}\\\\(f+g)(x)=(-x^2+3x^2)+(6x-4x)+(-1-1)\\\\(f+g)(x)=2x^2+2x-2

8 0
4 years ago
Find the 30th term of the following sequence. 1, 7, 13, 19, ... 174 175 180 181.
Tems11 [23]
Checking if the sequence is an arithmetic sequence 7 - 1 = 6 13 – 7 = 6 Therefore the sequence is arithmetic, with a_0 = 1 and d = 6 a_n = a_0 + (n-1)d a_30 = 1 + (29)(6) = 175 Therefore the 30th term is 175.
6 0
3 years ago
Read 2 more answers
Add. (3b + 5) + (2b + 4)
zaharov [31]

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

4 0
3 years ago
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