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3 years ago

BRAINLIEST PLEASE HELP np If f(x)=-x^2+6x-1 and g(x)=3x^2-4x-1, find (f+g)(x)

Mathematics

1 answer:

raketka [301]3 years ago

8 0

Answer:

$\large\boxed{B.\ (f+g)(x)=2x^2+2x-2}$

Step-by-step explanation:

$f(x)=-x^2+6x-1\\\\g(x)=3x^2-4x-1\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute:}\\\\(f+g)(x)=(-x^2+6x-1)+(3x^2-4x-1)\\\\(f+g)(x)=-x^2+6x-1+3x^2-4x-1\qquad\text{combine like terms}\\\\(f+g)(x)=(-x^2+3x^2)+(6x-4x)+(-1-1)\\\\(f+g)(x)=2x^2+2x-2$

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HELP PLEASE, LOOK AT PICTURE FOR WHOLE PROBLEM.. PLEASE ANSWER QUICK I DON'T HAVE MUCH TIME LEFT TO ANSWER

tatiyna

Answer:

2 $\sqrt{8}$

Step-by-step explanation:

According to Euclidian theorem :

h^2 = 4*8

h^2 = 32 find the root for both sides

h = 2 $\sqrt{8}$

4 0

2 years ago

Please answer fast!!!!!

BlackZzzverrR [31]

Answer:

x = 2

Step-by-step explanation:

note that 4096 = $8^{4}$ , then

$8^{2x}$ = $8^{4}$

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2x = 4 ( divide both sides by 2 )

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3 years ago

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For every 3 wrapped packages Mary uses 1/2 roll of wrapping paper how many packages can she wrap with 2 1/2 rolls of wrapping pa

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She can wrap 15 packages :)

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3 years ago

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The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

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3 years ago

Please answer <br> ( will give brainlst)

serg [7]

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2 years ago

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