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3 years ago

Add. (3b + 5) + (2b + 4)

Mathematics

1 answer:

zaharov [31]3 years ago

4 0

Answer:

$\huge{ \fbox{ \sf{5b + 9}}}$

Step-by-step explanation:

$\star{ \text{( \: 3b + 5) + (2b + 4)}}$

$\text{Step \: 1 \: : \sf{Remove \: the \: unnecessary \: parentheses}}$

$\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}$

$\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}$

$\mapsto{ \sf{3b + 5 + 2b + 4}}$

$\text{Step \: 2 \: : Collect \: like \: terms.}$

$\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}$

$\mapsto{ \sf{3b + 2b + 5 + 4}}$

$\mapsto{ \sf{5b + 5 + 4}}$

$\text{ Step \: 3 \: : \sf{Add \: the \: numbers : 5 \: and \: 4}}$

$\mapsto{ \boxed {\sf{ {5b + 9}}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

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In the third degree polynomial function f(x) =x^3 + 4x, why are 2i and -2i zeros?

IgorC [24]

Answer:

We just need to evaluate and get f(2i)=0, f(-2i)=0.

Step-by-step explanation:

Since $i^2=-1$ , then $i^3=i^2i=-i$ , and we can apply this when we evaluate $f(x) =x^3 + 4x$ for 2i and -2i.

First we have:

$f(2i) =(2i)^3 + 4(2i)=2^3i^3+8i=8(-i)+8i=0$

Which shows that 2i is a zero of f(x).

Then we have:

$f(-2i) =(-2i)^3 + 4(-2i)=(-2)^3i^3-8i=-8(-i)-8i=8i-8i=0$

Which shows that -2i is a zero of f(x).

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3 years ago

A necklace regularly sells for $18.00. the store advertises a 15% discount. what is the sale price of the necklace in dollars

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I can solve with 2 methods:

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II. The discount is 15 % of 18$
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Personally I believe the first is an easier method.
I hope you understand and you can apply this in every similary problem.

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Answer:

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