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anyanavicka [17]
2 years ago
11

Add. (3b + 5) + (2b + 4)

Mathematics
1 answer:
zaharov [31]2 years ago
4 0

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)
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Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

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<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

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<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

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