Answer:
x = 0
y = -2
Step-by-step explanation:
The given system of equation are:
5x + y = -2
2x - 2y = 4
The problem here is to find x and y from the expression
5x + y = -2 ----- i
2x - 2y = 4 ---- ii
So;
i x 2 : 10x + 2y = -4 ---- iii
ii x 5 : 10x - 10y = 20 ----- iv
iii - iv; 12y = -24
y = -2
Now find x;
5x + y = -2
5x - 2 = -2
x = 0
Solve for x:
8 - 5 x = 2 x + 8
Subtract 2 x from both sides:
8 + (-5 x - 2 x) = (2 x - 2 x) + 8
-5 x - 2 x = -7 x:
-7 x + 8 = (2 x - 2 x) + 8
2 x - 2 x = 0:
8 - 7 x = 8
Subtract 8 from both sides:
(8 - 8) - 7 x = 8 - 8
8 - 8 = 0:
-7 x = 8 - 8
8 - 8 = 0:
-7 x = 0
Divide both sides of -7 x = 0 by -7:
(-7 x)/(-7) = 0/(-7)
(-7)/(-7) = 1:
x = 0/(-7)
0/(-7) = 0:
Answer: x = 0
I believe the answer is 45.
Answer:
straight line add up to 180 so subtract 42 from 180 thts ur answer
- Given, x > 0, y > 0.
- So, the values of x and y are less than 0, that means, they are negative integers.
- If we divide a Cartesian plane with the x-axis and y-axis, we get four quadrants.
- 1st Quadrant : (+,+)
- 2nd Quadrant : (-,+)
- 3rd Quadrant : (-,-)
- 4th Quadrant : (+,-)
- Since the values of x and y are both negative, so (x, y) is located in the <em><u>3rd Quadrant</u></em>.
Hope you could get an idea from here.
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