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irina [24]
2 years ago
10

The circumference of the hub cap of a tire is 83.21 centimeters. Find the area of this hub cap. Use

Mathematics
2 answers:
finlep [7]2 years ago
8 0

Answer:

Area = 551 cm² (nearest whole number)

Step-by-step explanation:

<h3><u>Circumference</u></h3>

\textsf{Circumference of a circle}=\sf 2 \pi r\quad\textsf{(where r is the radius)}

Given:

  • Circumference = 83.21 cm
  • π = 3.14

Substituting the given values into the formula and solving for r:

\begin{aligned}\implies \sf 83.21 & =\sf 2 \cdot 3.14 \cdot r\\\\\sf r & = \sf \dfrac{83.21}{2 \cdot 3.14}\\\\\sf r & = \sf 13.25\:cm\end{aligned}

<h3><u>Area</u></h3>

\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

Given:

  • r = 13.25 cm
  • π = 3.14

\begin{aligned}\implies \sf Area & =\sf 3.14 \cdot 13.25^2\\\\& = \sf 551\:cm^2\:(nearest\:whole\:number)\end{aligned}

If the circumference of the hub cap was smaller, the radius would be smaller, hence the area would be smaller.

Elena L [17]2 years ago
7 0

Answer:

<u>551 square centimeters</u>

Step-by-step explanation:

Finding the radius (r) :

  • C = 2πr
  • 83.21 = 2 x 3.14 x r
  • 83.21 = 6.28r
  • r = 83.21/6.28
  • r = 13.25 cm

Finding the area :

  • A = πr²
  • A = 3.14 x (13.25)²
  • A = 3.14 x 175.5625
  • A = <u>551 square centimeters</u> (nearest whole number)

<u></u>

The area of this hub cap is about <u>551 square centimeters</u>.

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Step-by-step explanation:

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PLEASE HELP 25 POINTS!!
eduard

Answer:

(27 y^(-8))/(4 x^6)

Step-by-step explanation:

Simplify the following:

(4 (3 x^2 y^4)^3)/(2 x^3 y^5)^4

Multiply each exponent in 2 x^3 y^5 by 4:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^(4×5))

4×5 = 20:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^20)

4×3 = 12:

(4 (3 x^2 y^4)^3)/(2^4 x^12 y^20)

2^4 = (2^2)^2:

(4 (3 x^2 y^4)^3)/((2^2)^2 x^12 y^20)

2^2 = 4:

(4 (3 x^2 y^4)^3)/(4^2 x^12 y^20)

4^2 = 16:

(4 (3 x^2 y^4)^3)/(16 x^12 y^20)

Multiply each exponent in 3 x^2 y^4 by 3:

(4×3^3 x^(3×2) y^(3×4))/(16 x^12 y^20)

3×4 = 12:

(4×3^3 x^(3×2) y^12)/(16 x^12 y^20)

3×2 = 6:

(4×3^3 x^6 y^12)/(16 x^12 y^20)

3^3 = 3×3^2:

(4×3×3^2 x^6 y^12)/(16 x^12 y^20)

3^2 = 9:

(4×3×9 x^6 y^12)/(16 x^12 y^20)

3×9 = 27:

(4×27 x^6 y^12)/(16 x^12 y^20)

4/16 = 4/(4×4) = 1/4:

(27 x^6 y^12)/(4 x^12 y^20)

Combine powers. (27 x^6 y^12)/(4 x^12 y^20) = (27 x^(6 - 12) y^(12 - 20))/4:

(27 x^(6 - 12) y^(12 - 20))/4

6 - 12 = -6:

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12 - 20 = -8:

Answer: (27 y^(-8))/(4 x^6)

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