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irga5000 [103]
3 years ago
6

What is the value of the expression (9+15) / 3+2

Mathematics
2 answers:
sammy [17]3 years ago
5 0
Doing the numerator first, 9+15=24 and this is divided by 3+2=5 so it is 24/5 =4.8. 
morpeh [17]3 years ago
5 0

Answer

Find out the value of expression

\frac{(9 +15)}{3+2}

To prove

As the expression given in the question be

=\frac{(9 +15)}{3+2}

now first add the terms given in bracket in the numenator .

=\frac{(24)}{3+2}

now add the terms given in the denominator.

=\frac{(24)}{5}

= 4.8

Therefore the the value of expression \frac{(9 +15)}{3+2} is \frac{(24)}{5} is 4.8 (in decimal form) .





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Afina-wow [57]
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Cross multiply and divide:

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Elden [556K]

Answer:the greatest number of shirts she can buy = 8

Step-by-step explanation:

Amount of money Olivia  has =$90

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such that if she buys the pair of jean, Money left to buy shirts = $90-$22= $68

If 1 Shirt= $8

Number of shirts she can buy with $68 = $68/$8=  8.5= 8 1/2

Therefore the greatest number she can buy = 8 shirts.

6 0
3 years ago
The parent function f(x) = x2 is translated such that the function g(x) = –x2 + 6x – 5 represents the new function. What is true
kkurt [141]

Answer:

1. Translation 3 units to the right;

2. Reflection across the x-axis;

3. Translation 4 units up.

Step-by-step explanation:

First, rewrite the function g(x) in following way:

g(x)=-x^2+6x-5=-(x^2-6x)-5=-(x^2-6x+9-9)-5=-(x-3)^2+9-5=-(x-3)^2+4.

Apply such transformations:

1. Translate the graph of the parent function f(x) 3 units to the right to get the graph of the function f_1(x)=(x-3)^2.

2. Reflect the graph of the function f_1(x) across the x-axis to get the graph of the function f_2(x)=-(x-3)^2.

3. Translate the graph of the function f_2(x) 4 units up to get the graph of the function g(x)=-(x-3)^2+4.

8 0
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SVETLANKA909090 [29]

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We have

\dfrac{1+\sin x}{\sin x}\\\\\\=\dfrac{1}{\sin x}+\dfrac{\sin x}{\sin x}\\\\\\=1+\dfrac{1}{\sin x}.

In order to verify the given trigonometric equation, we must have

1+\dfrac{1}{\sin x}=1+\csc x\\\\\\\Rightarrow \dfrac{1}{\sin x}=\csc x\\\\\\\Rightarrow \csc x=\dfrac{1}{\sin x}.

Thus, the required identity that we will use is

\csc x=\dfrac{1}{\sin x}.

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Answer:

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