2 of 2 X= 1 True False

Mathematics

1 answer:

stepan [7]3 years ago

4 0

Answer:

of means to multiple so it would equal 4 so the answer is false

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Please answer i need help quick

Serjik [45]

Answer:

(-2, 6)

Step-by-step explanation:

Since you want a 1 to 7 ratio, you want to divide the line into 2 parts, where one part has a length of 1 and the other has a length of 7. So the total length of the line is 8.

Start by looking at the difference in the X and Y coordinates.

X = | -4 - 12 | = | -16 | = 16

Y = | 7 - -1 | = | 8 | = 8

You could calculate the length of the line using pythagorian's theorem, but that's not needed. Simply use similar triangles. We have a right triangle with legs of length 16 and length 8. We want a similar triangle that is 1/8th as large (to get the desired 1 to 7 ratio). So divide both legs by 8, getting lengths of 16/8 = 2, and 8/8 = 1.

Now add those calculated offsets to point A.

A has an X coordinate of -4 and B has an X coordinate of 12 and the X coordinate for C must be between those limits. So calculate -4 + 2 = -2 to get the X coordinate for C.

The Y coordinate of A is 7 and the Y coordinate of B is -1. And since the Y coordinate must be between then, you have 7 - 1 = 6.

So the coordinates for C is (-2, 6)

8 0

3 years ago

Bob is throwing a party. He had 22 pints of soda. At the end of the party, there are 8 pints of soda. How many cups of soda were

Ksivusya [100]

Answer:

14 pints were drank

Step-by-step explanation:

22 pints - 8 pints =

7 0

2 years ago

Find the distance between the points of intersection of the graphs of the functions.

Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

${ \rm{y = {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\ \\ { \rm{(x + 1) = {x}^{2} - 3x + 4 }} \\ \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\ \\ { \rm{(x - 3)(x - 1) = 0}} \\ \\ { \boxed{ \rm{x_{1} = 3 \: \: and \: \: x _{2} = 1}}} \\ \\ { \boxed{ \tt{remember \: y = x + 1}}} \\ \\ { \rm{y _{1} = 4 \: \: and \: \: y _{2} = 2 }}$

Therefore, points of intersection are two

Answer:  (3, 4) and (1, 2)

Question 2:

Following the steps as in question 1

${ \rm{y = {x}^{2} - 4}} \\ \\{ \rm{2x - 4 = {x}^{2} - 4}} \\ \\ { \rm{ {x}^{2} = 2x }} \\ \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}$